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Find all values of k so that is invertible

WebAug 1, 2024 · Almost all square matrices are invertible. It is very special, i.e. singular, for a square matrix to be non-invertible. As you say, $\det = 2k^2-k^3-k^4$. This factorises to … WebIf e and f are both zero, there will be an infinite number of possible solutions. A = 0 means that ad = bc or a/c = b/d. Select n = c/a, which gives c = n*a, then you get these equation a/ (n*a) = b/d reduce and rearrange d = n*b The resulting equations become a*x + b*y = 0 c*x + d*y = n*a*x + n*d*y = 0

Find the values of k for which the matrix A is invertible. A

WebNov 6, 2024 · Find all values of K so A A T is symmetric My answer so far: QUESTION 1 d e t ( A) = 0 0 = ( 1) ( k − 2) ( k + 1) ( 3) 0 = ( k − 2) ( k + 1) ( 3) 0 = ( k − 2) ( 3 k + 3) 0 = 3 k 2 + 3 k − 6 k − 6 6 = 3 k ( k − 1) 6 / 3 k = k − 1 2 k = k − 1 k = − 1 QUESTION 2: I'm confused on how to even figure this question out, where exactly would I begin? WebFind all values of k so that [ k +1 3 2 k] −I 2 is invertible. To enter your answer, first select 'always', 'never', or whether k should be equal or not equal to specific values, then enter a value or a list of values separated by commas. Previous question Next question This problem has been solved! how to use lightscribe https://bowden-hill.com

linear algebra - Find all possible values of rank(A) as

WebAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators ... WebMath Algebra Find conditions on k that will make the matrix A invertible. To enter your answer, first select 'always', 'never', or whether k should be equal or not equal to specific values, then enter a value or a list of values separated by commas. k 19 –12 A= 8 k 8 -4 5 -4 A is invertible: Always WebIf the Kernel of a Matrix A is Trivial, then ATA is Invertible Let A be an m × n real matrix. Then the kernel of A is defined as ker(A) = {x ∈ Rn ∣ Ax = 0}. The kernel is also called the null space of A. Suppose that A is an m × n real matrix such that ker(A) = 0. Prove that ATA is […] Is an Eigenvector of a Matrix an Eigenvector of its Inverse? organised print

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Find all values of k so that is invertible

linear algebra - find all values of k for which A is invertible ...

WebFind all values of k for which A is invertible. k k 0A = k^2 2 k 0 k kNote: A is invertible if determinant of A does not equal 0 This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer Web1 Answer. Your first step is correct. Now multiply the second row by 2 3 ( 1 2 a − 2) and sum to the third line, so you find an upper triangular matrix: If a 2 − 8 3 a + 5 3 ≠ 0 the matrix is full rank, and this is done if a is different from 1, and 5 3 (the roots of a 2 − 8 3 a + 5 3 = 0 ). Substituting these values you see that the ...

Find all values of k so that is invertible

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WebNov 6, 2024 · 4 Answers. Dividing by your variable is always a bad idea for example if you divide 0 = x ∗ ( x − 5) by x you get x = 5 as a solution but not x = 0. gives you two … WebFind all values of c, if any, for which the given matrix is invertible (using row operations -> gotta try simplifying to I). Here is the matrix : ( c 1 0 1 c 1 0 1 c) linear-algebra. matrices. Share. Cite. Follow. edited Oct 4, 2014 at 15:39.

WebTour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site WebExpert Answer. 100% (1 rating) Transcribed image text: Find conditions on k that will make the matrix A invertible. To enter your answer, first select 'always', 'never', or whether k should be equal or not equal to specific values, then enter a value or a list of values separated by commas. A = [5 k 3 0 1 1 - 2 2 2]

WebTo enter your answer, first select 'always', 'never', or whether k should be equal or not equal to specific values, then enter a value or a list of values separated by commas. Invertible: When k = ??? Always INever Question 4 When k Given the detWhen k he following This problem has been solved! WebFind all values of k so that [k+1 4 9 k+1 is invertible To enter your answer, first select 'always', 'never', or whether k should be equal or not equal to specific values, then enter a value or a list of values separated by commas. Invertible: Always Always SUBMIT AND MARK SAVE AND CLOSE When k = When k7 Official Tim Never

WebOct 29, 2016 · For all Other values of C , Find $\... Stack Exchange Network Stack Exchange network consists of 181 Q&A communities including Stack Overflow , the largest, most trusted online community for developers to …

WebI've been given this question in class, with the 3x3 matrix: $$\begin{bmatrix} 2& 1& 0\\ 1 & 2 & 1\\ 0 & -3 & k\end{bmatrix}.$$ My job here is to find the Stack Exchange Network Stack Exchange network consists of 181 Q&A communities including Stack Overflow , the largest, most trusted online community for developers to learn, share their ... organised retail formatsWebDetermine the values of $k$ so that the following linear system has a unique solution, infinite solutions and no solution. $2x + (k + 1)y + 2z = 3$ how to use lightshot windows 10WebDecide whether the matrix is invertible, and if so, use the adjoint method to find its inverse. A = [2 0 3, 0 3 2, -2 0 -4] linear algebra. Find all values of x for which A is … organised rackWebFind all values of k so that [k+492k+1]−I2 is invertible. To enter your answer, first select 'always', 'never', or whether k should be equal or not equal to specific values, then enter a value or a list of values separated by commas. Invertible: Always This … how to use lightscribe softwarehow to use lightscribe on hp laptopWebthumb_up 100%. Transcribed Image Text: Find all values of k so that k 2 3 k+1 is invertible. -1₂ To enter your answer, first select 'always', 'never', or whether k should be … organised raft tour on medium breeding lakeWebFeb 3, 2015 · Now a reasonable step would be to divide the last row by ( k − 1). But this is only possible if k − 1 ≠ 0. So you can: Solve the case k = 1 separately. For k ≠ 1 divide the last row by ( k − 1) which leads you to a simpler matrix - you should try whether you are able to continue from there. [ 1 1 k 1 k 1 1 1 0 1 − 1 0] Share Cite Follow how to use lightshot on windows 10